Silver Atomic Mass

The density of silver having an atomic mass of 107.8 g mol^{- 1} is 10.8 g cm^-3. If the edge length of cubic unit cell is 4.05 × 10^{- 8}
cm, find the number of silver atoms in the unit cell.
( N_A = 6.022 × 10²³, 1 Å = 10^-8 cm)

1. Silver Atomic Mass Number
2. Atomic Mass Of Ag
3. Silver Nitrate Atomic Mass

Solution

Atomic Number: 47 Atomic Weight/Mass: 107.8682 amu Standard State: Solid, at 298 Degrees Kelvin ( 77 degrees Fahrenheit ) CAS ID: 7440-22-4 Group Number: 11 Class: Metal, Transition Melting Point of Silver: 961.93 °C Boiling Point of Silver: 2,212.0 °C. Number of Protons & Electrons: 47 Number of Nuetrons: 61 Crystal Structure of Silver. ››More information on molar mass and molecular weight. In chemistry, the formula weight is a quantity computed by multiplying the atomic weight (in atomic mass units) of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together. Name: Silver Symbol: Ag Atomic Number: 47 Atomic Mass: 107.8682 amu Melting Point: 961.93 °C (1235.08 K, 1763.474 °F) Boiling Point: 2212.0 °C (2485.15 K, 4013.6 °F) Number of Protons/Electrons: 47 Number of Neutrons: 61 Classification: Transition Metal Crystal Structure: Cubic Density @ 293 K: 10.5 g/cm 3 Color: silver Atomic Structure. Silicon has an atomic number of 14 and atomic mass Nickel has 28 protons, what is its atomic number? Silver has an atomic number of 47 and atomic mass of Neon has an atomic number of 10 and an atomic mass Silver has an atomic number of 47 and atomic mass of Silicon has an atomic number of 14 and atomic mass.

Given:
Density (d) = 10.8 g cm^-3
Edge length (a) = 4.05 x 10^{- 8} cm
Molar mass = 107.8 g mol^-1
Avogadro's number (N_A) = 6.022 x 10²³

To find:
Number of atoms in the unit cell

Formula:
a. Mass of one atom = `'Atomic mass'/'Avogadro number'`
b. Volume of unit cell = a³
c. Density = `'Mass of unit cell'/'Volume of unit cell'`

Calculation:
a) Mass of one Ag atom = `'Atomic mass of Ag'/'Avogadro number'`
Avogadro number
= `107.8/(6.022 xx 10^23)`

= 1.79 x 10^-22 g

b) Volume of unit cell = a³
= ( 4.05 x 10^-8 )³
= 6.64 x 10^-23 cm³
c)
Density (d) = `'Mass of unit cell'/'Volume of unit cell'`

= `'Number of atoms in unit cell x Mass of one atom'/'Volume of unit cell'`
10.8 = `('Number of atoms in unit cell' xx 1.79 xx 10^-22)/(6.64 xx 10^-23)` Movies to watch if you liked knives out full.

Number of atoms in unit cell = `( 10.8 xx 6.64 xx 10^-23)/( 1.79 xx 10^-22)` Convert to for mac.

Silver Atomic Mass Number

= 40.06 x 10^-1 = 4.0 ≈ 4

∴ The number of atoms in the unit cell of silver is 4.

Atomic Mass Of Ag

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Silver Nitrate Atomic Mass

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